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20x^2+16x+5=0-
We move all terms to the left:
20x^2+16x+5-(0-)=0
We add all the numbers together, and all the variables
20x^2+16x+5-0=0
We add all the numbers together, and all the variables
20x^2+16x+5=0
a = 20; b = 16; c = +5;
Δ = b2-4ac
Δ = 162-4·20·5
Δ = -144
Delta is less than zero, so there is no solution for the equation
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